Question

Q.12.Show that p- 1 is a factor of p^10 - 1 and also of p¹¹ - 1.​

Answer 1

Step-by-step explanation:

Let p-1=0

p=1

P^10 -1

= (1)^10 -1

=1-1

=0

Since, the remainder is 0, then p-1 is a factor of p^10-1.

p^11-1

=(1)^11-1

=1-1

=0

Since, the remainder is 0, then p-1 is a factor of p^11-1.

Answer 2

Answer:

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Here is Your Answer...!!

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Step by step solution:

$Given \ p(x)=p^{10}-1 \ and \ f(x)=p^{11}-1 \ and \ g(x)=p-1\\\\we \ have \ to \ show \ g(x) \ is factor \ of \ p(x) \ and \ f(x)\\\\putting \ g(x) \ value \ p-1=0\\\\p(1)=1^{10}-1=0\\\\f(1)=1^{11}-1=0\\\\Hence \ shown$

Hope it is clear to you