Question

Q 14plzzzzzzzzzz frienda

Answer 1

x^3+3x^2y+3xy^2+y^3 = (x+y)^3

hence, x^3+3x^2y+3xy^2+y^3-8 = (x+y)^3-8
= (x+y)^3-2^3
= (x+y-2)[(x+y)^2 + 2(x+y) + 4

now, expand it to get the answer.

for any doubts, pls comment