Q 14plzzzzzzzzzz frienda
Attachments:
Answers
Answered by
1
x^3+3x^2y+3xy^2+y^3 = (x+y)^3
hence, x^3+3x^2y+3xy^2+y^3-8 = (x+y)^3-8
= (x+y)^3-2^3
= (x+y-2)[(x+y)^2 + 2(x+y) + 4
now, expand it to get the answer.
for any doubts, pls comment
hence, x^3+3x^2y+3xy^2+y^3-8 = (x+y)^3-8
= (x+y)^3-2^3
= (x+y-2)[(x+y)^2 + 2(x+y) + 4
now, expand it to get the answer.
for any doubts, pls comment
ekta36:
hi
hi
ooo
what oooo ekta
nothing is
Similar questions