Q 17. Value of (x2y2 - 16) is ?
1) xy +4
2)(xy+4)(xy - 4)
3)xy +2xy-y2
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Answer:
= x²y² - 16
= (xy)² - 4² [ a² - b² = (a+b)(a-b) ]
= ( xy - 4 )( xy + 4 )
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