Question

Q.18 Two triangles ABC and DEF are such that AB=DE, BC=EF and median AMEDN.
Prove that AABC=ADEF.​

Answer 1

Answer:

in triangle ABM and triangle DEN

AB=DE(given)......1

BC=EF(given)......2

AM=DN

in a triangle, median divides the triangle into equal areas

triangle ABN= triangle ACN......3

triangle DEN =triangle DFN.......4

therefore, from 1,2,3,and 4

AC=DF

triangle ABC=triangle DEF