Question

Q.23 Find a quadratic polynomial whose zeroes are 5-3√2 and 5+3√2. ​

Answer 1

a = 5-3√2, b= 5+3√2

a+b= 5-3√2+5+3√2 = 10

a×b = (5-3√2)(5+3√2)

=5(3+3√2)-3√2(5+3√2)

= 15+15✓2-15✓2-18

=-3

x²-(a+b)x - a×b

x²- 10x - (-3)

x²-10x+3

Answer 2

Step-by-step explanation:

if a and b are zeros of polynomial, then

p(x) = x² - x (a + b) + ab

in tbe given problem, a = 5 - 3√2 and b = 5 + 3√2

p(x)=x²-x [5-3√2+5+3√2]+(5-3√2)(5+3√2)

p(x) = x² - x [10] + [25 - 18]

p(x) = x² - 10x + 7