Question

Q.74. A projectile attains a maximum height of 100 m and has a horizontal range of 400 m. Find the angle
at which it is projected and the velocity of projection. ​

Answer 1

Answer:

hope its helpful.

Explanation:

maximum height reached = H = 100 m,

horizontal range = R = 400m, g = 9.8 m/s2. To Find: Angle of projection = θ =?, velocity of projection = vo =?

Answer 2

Answer: hope you can understand this