Q. a block of mass 5 kg was at rest on a horizontal frictionless surface. if it is pushed with a force of magnitude 60n in a direction 40° above the the +x axis, how fast is the block moving at the End of 6s?
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Answer:
Using work-energy theorem:
W.Dforce+W.Dfriction=ΔK.E
45×2−25×2=KEfinal
KE final=40 J
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175
Explanation:
it is very simple okay
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