Q a boy run 100 m along the east then turns to his left at right angle and runs for 50 m along the north direction. find the distance and magnitude of displacement of the body.
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Answered by
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DISTANCE IS 100+50=150 M
DISPLACEMENT =ROOT OF (100^2+50^2)
=111.802 M TOWARDS NORTH EAST.
I HOPE THIS HELPS U ...
DISPLACEMENT =ROOT OF (100^2+50^2)
=111.802 M TOWARDS NORTH EAST.
I HOPE THIS HELPS U ...
Answered by
2
the total distance traveled by the boy =100 m+50 m
=150 m .
the total displacement is the =111.8 m i have got this answer by the process of Pythagoras theorem in which perpendicular is 50 m and base is 100 m and then i have joined the line of perpendicular from the line of base
hope that this will help u.
=150 m .
the total displacement is the =111.8 m i have got this answer by the process of Pythagoras theorem in which perpendicular is 50 m and base is 100 m and then i have joined the line of perpendicular from the line of base
hope that this will help u.
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magnitude means the numerical value.