Question

Q. Find the distance of the point ( 3,-5) from the line 3x-4y-26=0.

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Answer 1

Answer:

3/5

Step-by-step explanation:

(x₁,y₁) = (3,-5)

Ax + By + C = 0

3x - 4y - 26 = 0

On comparing,

A = 3, B = -4, C = -26

x₁ = 3, y₁ = -5.

The distance from point (x₁, y₁) to the line Ax + by + C = 0.

d = |Ax₁ + By₁ + C|/√A² + B²

  = |3(3) + (-4)(-5) + 26}/√(3)² + (-4)²

 = 3/5

Therefore, distance = 3/5.

#Hope my answer helped you!