Q find the sum of A.P 2,7,12,.....to 10 terms
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2,7,12,....10 terms are in AP First term =a =2
Common difference(d) = 7-2 =5
________________
Sum of n terms
(Sn) = n/2[2a+(n-1)d]
_________________
S10 =( 10/2)[2*2+(10-1)*5] =5*[4+45]
=5*49
=245
Therefore,
Sum of 10 terms in given
A.P = 245
••••
Common difference(d) = 7-2 =5
________________
Sum of n terms
(Sn) = n/2[2a+(n-1)d]
_________________
S10 =( 10/2)[2*2+(10-1)*5] =5*[4+45]
=5*49
=245
Therefore,
Sum of 10 terms in given
A.P = 245
••••
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