Q.In a rhombus,if diagonals are 30cm and 40cm,find its perimeter....
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Answers
Answer:
The diagonals of a rhombus are perpendicular bisectors of each other.
The sides of a rhombus are equal in measures.
30/2 = 15 , 40/2 = 20 bisectors of diagonals
Side of the rhombus becomes hypotenuse.
(Side)^2 =(15)^2+( 20)^2 (Pythagoras Theorem)
(Side)^2= 225 + 400
(Side)^2 = 625
Side = + or - 25 (taking square root)
Discarding the negative sign , side = 25 cm
perimeter = 4*side =4*25 =100 cm
˙·٠•●♥ ANS : 100CM ♥●•٠·˙
Answer:
The perimeter of the Rhombus is 100 cm.
Step-by-step explanation:
Given:
Diagonals = 30 cm and 40 cm
To find:
The perimeter
Solution:
Using the Pythagoras Theorem to find the side of the Rhombus. (The diagonals bisect each other)
Hypotenuse = x
Base = 20 cm
Height = 15 cm
★ (Hypotenuse)² = (Base)² + (Height)²
⇒ (x)² = (20)² + (15)²
⇒ x² = 400 + 225
⇒ x² = 625
⇒ x = √625
⇒ x = 25
Side = 25 cm
The side of the Rhombus = 25 cm
★ Perimeter = Side × 4
⇒ 25 × 4
⇒ 100 cm
Therefore, the perimeter of the Rhombus is 100 cm.