Question

Q- In fig. l1 || l2 the value of X is:
(a)80° (b)100° (c)110° (d)70°

solution- Angle1+Angle45°+Angle 35°=180°
Angle1=180°-80°
Angle1=100°
Angle1+Angle2=180°
100°+Angle2=180°
Angle2=180°-100°
Angle2=80°

X=Angle2 (Corresponding angle)
X=80°
​

Answer 1

Step-by-step explanation:

80 is the answer marke me brainliest

Answer 2

Solution :-

In given ∆, we have,

→ y + 45° + 35° = 180° { By angle sum property. }

→ y + 80° = 180°

→ y = 180°- 80°

→ y = 100°

So,

→ y (between parallel lines) = 100° { Vertically opposite angles. }

then,

→ x + y = 180° { since l1 || l2 , corresponding angles }

→ x + 100° = 180°

→ x = 180° - 100°

→ x = 80° (a) (Ans.)

Learn more :-

In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .

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