Question

Q:-solve this and then find pq
${a}^{4} + {b}^{4} = ( {a}^{2} + pab + {b}^{2} )( {a}^{2} - qab + {b}^{2} )$
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Answer 1

Step-by-step explanation:

4(2 + x) = 8⟹−4(2+x)=8

8 - 4x = 8⟹−8−4x=8

8 - 8 = 4x⟹−8−8=4x

16 = 4x⟹−16=4x

4x = - 16⟹4x=−16

x = - \frac{16}{4} = - 4⟹x=−

4

16

=−4

⟹x = - 4⟹x=−4

Check:-

- 4(2 - 4) = 8⟹−4(2−4)=8

- 4( - 2) = 8⟹−4(−2)=8

8 = 8⟹8=8