Math, asked by aman9057, 9 months ago

q wall of a hall is to be fixed with marble tiles.the length and breath of the walls is 14m and 10m respectively.how many square of tiles will be requried to cover the wall if the side of the tile is 10cm.​

Answers

Answered by Lekhashree11
1

Step-by-step explanation:

Area of the wall = 14 × 10

= 140 sq.m

Area of the square = 10 × 10 × 10^-4

= 10^-2 sq.m

Now, n × area of square = area of rectangle

n × 10^-2 = 140

n = 140 × 10^2

= 14000

Therefore 14000 tiles are required to cover the wall.

HOPE THIS HELPS YOU......

Answered by anik75biswas84
0

Answer:

140 tiles requires to cover the wall

Step-by-step explanation:

Length of the hall = 14 m

Breadth of the hall = 10 m

∴ Area of the hall = 14*10

                             = 140 m²

Length of the Side of the Square tile = 10 cm

So, Area of the Square tile = S*S

                                            = 10*10

                                            = 100 cm²

                                            = 1m² ( Converted into meter )

∴ No.of walls required to cover the wall = Area of the wall / Area of the tile

                                                                  = 140/1

                                                                  = 140 tiles (Ans)

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