Q1. Derive the equations of motion (i) ?= u + at (ii) S = ut + 12 at2 and (iii) 2 aS = ? − u2, by graphical method
Answers
Answer:
GRAPH FOR 1st AND 2nd EQUATION OF MOTION IS SAME.
Explanation:
Answer:
1.
We know :
Acceleration = Change in velocity / Change in time.
Let :
Initial velocity be u and final velocity be v also time t .
=> a = Δ v / Δ t
= > a = ( v - u ) / t - 0
= > a t = v - u
= > v = u + a t .
2.
We know :
Average velocity = Total distance covered / Total time taken.
= > ( v + u ) / 2 = s / t
= > s = ( v + u ) t / 2
From equation first we have :
v = u + a t
= > s = ( u + a t + u ) t / 2
= > s = ( 2 u + a t ) t / 2
= > s = u t + 1 / 2 a t²
3.
We know first equation :
v = u + a t
Squaring both side :
v² = ( u + a t )²
= > v² = u² + a² t² + 2 u a t
= > v² = u² + 2 u a t + a² t²
Take out '2 a' common :
= > v² = u² + 2 a ( u t + 1 / 2 a t² )
Using equation second we get :
= > v² = u² + 2 a s