Question

Q1. IOf one root xsquare-ax-4= is negative of the other then the value of a is a)0 b)1 c)2 d)4

Answer 1

Let f(x) = $x^{2}-ax-4=0$
And let one root be $\alpha$
Then as per as question, other root is-$\alpha$
And we know that sum of root is equal to the negative of coefficient of x by coefficient of $x^{2}$

Therefore, $\alpha$ + (-$\alpha$) = 0
=>-(a/1)= 0
=>a =0
So, the value of a is 0. The correct option is (a)