Question

Q1) sin15 cos75+cos15 sin75

tan5 tan30tan35 tan55 tan85

plzz... ans me this que as fast as u can.... tanx in advance.. :)

Answer 1

1) sin 15° cos 75° + cos 15° sin 75°

= sin (15° + 75°) [∵ sin a cos b + cos a sin b = sin (a + b)]

= sin 90° = 1



2) tan 5° tan 30° tan 35° tan 55° tan 85°

= tan 5° tan 30° tan 35° cot 35° cot (90° – 55°) cot (90° – 85°)

∴ tan θ = cot (90 – θ)

= tan 5° tan 30° tan 35° cot 35° cot 5°

= tan 30° (∵ tan θ × cot θ = 1)
=1/√3
I hope this will help you
if not then comment me

Answer 2

$<h6>$sin15 cos75 + cos15 sin75 = sin(15+75) = sin90 = 1

tan5 tan30 tan35 tan55 tan85 = (1/sqrt3)[tan5 tan35 tan(90-35) tan(90-5)]
                                               = (1/sqrt3)[tan5 tan35 cot35 cot5] = 1/sqrt3

the expression = sqrt3