Math, asked by grovernaresh961, 4 months ago

Q1.Two bodies of equal weight
are kept at heights of h and 1.5
h, respectively. The ratio of
their PE is​

Answers

Answered by Anonymous
3

\huge\green{Question}Two bodies of equal weight  are kept at heights of h and 1.5 h, respectively. The ratio of  their PE is​

\huge\red{Answer}⇒2.3

\huge\orange{Explanation}

Potential energy is mathematically defined as P.E = mgh

Potential energy of body 1 = P.E._{1} =mgh_{1}

Potential energy of body 2  = P.E._{2} =mgh_{2}

Since weight of two bodies are equal,

Therefore  \frac{P.E._{1} }{P.E._{2} } =\frac{h}{1.5h} =\frac{2}{3}

Hence the ratio of their P.E is 2:3

\huge\pink{hope\;it\;helps}

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