Q2) From the sum of 3x-y +z and-y-z subtract 3x-y-z. What is the coefficient of x in the
result?
Answers
Answered by
9
We have to find:
[(3x - y + z) + (-y - z)] - (3x - y - z)
= [3x - y + z - y - z] - (3x - y - z)
= (3x - 2y) - (3x - y - z)
= 3x - 2y - 3x + y + z
= 3x - 3x - 2y + y + z
= -y + z
[(3x - y + z) + (-y - z)] - (3x - y - z)
= [3x - y + z - y - z] - (3x - y - z)
= (3x - 2y) - (3x - y - z)
= 3x - 2y - 3x + y + z
= 3x - 3x - 2y + y + z
= -y + z
Answered by
14
ANSWER: 0
Step-by-step explanation:
3x-y+z +(-y-z)
= 3x-y+z -y-z
= 3x-2y-0
= 3x-2y ------- equation 1
let 3x-y-z be equation 2
now adding equation 1 and 2
= 3x- 2y -(3x-y-z )
= 3x- 2y -3x + y +z
=0x -y +z
so the coefficient of x is 0
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