Q20. There are two bags containing white and black balls. In the first bag, there are 8 white and 6 black balls and in the second bag, there are 4 white and 7 black balls. One ball is drawn at random from one of the two bags chosen at random. Find the probability of this ball being black.
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3
Answer:
Step-by-step explanati
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19
Answer:
Probability of getting a black ball is 41/77.
Step-by-step explanation:
Given:
Bag 1 = 8 white balls and 6 black balls
Bag 2 = 4 white balls and 7 black balls.
To find: Probability of getting a black ball from the bag.
Total balls in bag 1 = 8 + 6 = 14
Total balls in bag 2 = 4 + 7 = 11
First we have to select a bag and then we will draw a ball.
Probability of selection of both bags is equal = 1/2
Probability of black ball taken from bag 1 = (1/2) x (6/14) = 3/14
Probability of black ball taken from bag 2 = (1/2) x (7/11) = 7/22
Thus,
Probability of black ball = 3/14 + 7/22 = 41/77
Therefore, Probability of getting a black ball is 41/77.
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