Question

Q3) The amount of magnesium
sulphide obtained from 1.0 gm of
Magnesium & 1.0 gm of Sulphur is:
[Mg = 24, S = 32]
*
O (a) 1.00 gm
O (b) 1.75 gm
O (c) 3.75 gm
(d) 2.75 gm​

Answer 1

Answer:

C=1.75g

Amount of MgS is 1.75g