Question

Q30. The no. of silver atoms present in a 90% pure silver wire weighing 10 g. is (at.wt. of Ag=108)
(a) 8x10^22
(b) 0.62x10^23
(c) 5x10^27
(d) 6.2x10^29​

Answer 1

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What is the number of silver atoms present in a 90% pure silver wire weighing 10g? The atomic weight of Ag is 107.8682. Then use the Avogadro constant to convert mol to number of atoms. 5.0246E23 atoms of Ag or 50 sextillion 246 quintillion atoms of silver.

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