Math, asked by aditya5shyam, 20 days ago

Q39.The perimeter of a rhombus is 20 cm. If one of its diagonals is 6 cm, then its area is (a) 24 cm square (b) 20 cm square (C) 36 cm square (d) 28 cm square

Answers

Answered by adithyakumar0252
1

Answer:

Solution

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Let first diagonal be d

Second diagonal be d

2

Giver perimeter of a rhombus =20cm

We know perimeter of a rhombus =4 sides

Hence, side =

4

20

cm=5cm

Now, we know that the diagonals of a rhombus bisect each other at right angles (90°)

Hence, a right angled triangle can be visualized with side as hypotenuse.

Diagonal length =8cm

Half the length ( since diagonal bisect each other ) =

2

8

=4cm

⇒(

2

d

)

2

+(

2

d

2

)

2

=5

2

⇒(

2

8

)

2

+(

2

d

2

)

2

=25

⇒4

2

+(

2

d

2

)

2

=25

⇒(

2

d

2

)

2

=25−16

⇒(

2

d

2

)

2

=9

⇒(

2

d

2

)

2

=

9

2

d

2

=3

⇒d

2

=6cm

Hence other diagonal =6cm

Area =

2

1

×d×d

2

=

2

1

×8×6

=24cm

2

.

Hence, the answer is 24cm

2

.

Answered by raiv9087
0

Answer:

This is your answer in the Given pic

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