Math, asked by satyamthapa1212, 3 months ago

Q6. The population of a town decrease by 10% during the first year, decrease by 15%
during the second year and again decreases by 20% during the third year. If the present
population of the town is 15300 then what was the population of the town three years
ago?

Answers

Answered by mahipatel010701
0

Answer:

Answer is 17,280.

Full answer is photo below.

Step-by-step explanation:

I hope this answer is you useful.

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Answered by priyarksynergy
0

The answer is this problem is as follows:

Step-by-step explanation:

present population: 10,000

Increase in year 1= 20%

hence,

20% of 10,000= 20/100 × 10,000

= 2000

Population in year 2 = 12,000

Increase in year 2 = 20%

∴ 20/100 × 12,000

= 2400

Population in year 3 = 14,400

Increase in year 3 =20%

∴ 20/100 × 14,400

= 2880

Therefore,

Population after 3 years is:

=17,280

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