Question

Qa and PB are perpendiculars to AB. If AO=10cm , OB=6cm , PB=9cm. Find AQ .
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Answer 1

In triangles AOQ and BOP, we have

∠OAQ=∠OBP [Each equal to 90∘]

∠AOQ=∠BOP [Vertically opposite angles]

Therefore, by AA-criterion of similarity

△AOQ∼△BOP

⇒AO/BO =OQ/OP=AQ/BP

⇒AO/BO=AQ/BP

⇒10/6=AQ/9

⇒ AQ= (10×9)/6 =15cm

Answer 2

ok.. sorry for answering irrelevant...

But can you please report all my unnecessary questions not related to studies.

Thanks .