Question

Quadratic Surd of √π​

Answer 1

So, the point is , if radicands are irrational & index is 2 ( square root) , such irrational numbers are called QUADRATIC SURDS. Example: √(√2) , √(5+√6) , √(any irrational numbers) are all Quadratic Surds. So, √pi is a quadratic Surd.

Step-by-step explanation:

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Answer 2

$\sf surd [\pi,2] = \pm \sqrt{\pi}$

$\sf surd [\pi,2] \approx \pm1.7724$

And, considering the principal value surd.

$\bf \sqrt{\pi} \approx1.7724$

which is an irrational and transcendental or non-algebraic number.