quadrilarerial hai please help
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In a Quadrilateral given that :
Angle P = ?
Angle Q = 2 Angle P
Angle R = 3 Angle P
Angle S = 30°
Now
Angle P + Angle Q + Angle R + Angle S = 360°
( Angle Sum Property of Quadrilateral )
Therefore
Angle P + (2 Angle P) + (3 Angle P) + 30° = 360°
6 Angle P = 360 - 30
6 Angle P = 330°
Angle P = 330 / 6 = 55 °
So
Angle P = 55°
Angle Q = 2 Angle P = 2 × 55 = 110°
Angle R = 3 Angle P = 3 × 55 = 165°
Angle S = 30°
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Angle P = ?
Angle Q = 2 Angle P
Angle R = 3 Angle P
Angle S = 30°
Now
Angle P + Angle Q + Angle R + Angle S = 360°
( Angle Sum Property of Quadrilateral )
Therefore
Angle P + (2 Angle P) + (3 Angle P) + 30° = 360°
6 Angle P = 360 - 30
6 Angle P = 330°
Angle P = 330 / 6 = 55 °
So
Angle P = 55°
Angle Q = 2 Angle P = 2 × 55 = 110°
Angle R = 3 Angle P = 3 × 55 = 165°
Angle S = 30°
Hope you like it please mark as brainliest and follow me if you like my answer.
satendarkumar9p7y0d3:
thank you shubh
Answered by
1
Answer:
Step-by-step explanation:
sum of angles of quadrilateral is 360
so,
angle P+angle Q+angle R+angle S=360
substituting given,
P+2P+3P+30=360
6P=330
P=55
Q=110
R=165
checking,
55+165+30+110=360
best of luck :)
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