Question

quadrilateral E F G H is a rectangle in which Jay is the point of intersection of the diagonals find the value of x if j f is equal to 8 x + 4 and easy equal to 24 x -8 ​

Answer 1

Step-by-step explanation:

EFGH is a rectangle. The diagonals of a rectangle are equal in length and bisect each other at their point of intersection (here, J).

FH=EG and FJ= FH/2

=> FJ= EG/2

$= > 8x + 4 = \frac{24x - 8}{2} \\ 4(2x + 1) = 8( \frac{3x - 1}{2} ) \\ 2x + 1 = \frac{8}{4 \times 2} ( 3x - 1) \\ 2x + 1 = 3x - 1 \\ x = 2$

Hence, the value of x is 2 units.

Answer 2

Answer:

Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals. The value of x if JF = 8x + 4 and EG = 24x - 8, is 2.

Step-by-step explanation:

The length of both the diagonals of rectangle are equal.

Hence , FH=EG

as, diagonals bisect each other 

So,2(JF)=EG 

2(8x+4)=(24x−8) 

16x+8=24x−8

8x=16 

x=2