quadrilateral E F G H is a rectangle in which Jay is the point of intersection of the diagonals find the value of x if j f is equal to 8 x + 4 and easy equal to 24 x -8
Answers
Answered by
2
Step-by-step explanation:
EFGH is a rectangle. The diagonals of a rectangle are equal in length and bisect each other at their point of intersection (here, J).
FH=EG and FJ= FH/2
=> FJ= EG/2
Hence, the value of x is 2 units.
Answered by
0
Answer:
Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals. The value of x if JF = 8x + 4 and EG = 24x - 8, is 2.
Step-by-step explanation:
The length of both the diagonals of rectangle are equal.
Hence , FH=EG
as, diagonals bisect each other
So,2(JF)=EG
2(8x+4)=(24x−8)
16x+8=24x−8
8x=16
x=2
Similar questions