Question

Que-) Without finding the cubes, factorise: (x -2y)3 + (2y-3z)3 + (3z –x)3.

Answer 1

Answer:

we know that a+b+c=0

Step-by-step explanation:

(x-2y)^3+(2y-3z)^3+(3z-x)^3

3(x-2y) (2y-3z) (3Z-x) ans

Answer 2

Answer:

hey mate ❤️.....here is your answer.....

let,

(x-2y)=a

(2y-3z)=b

(3z-x)=c

now,

.a+b+c=x-2y+2y-3z+3z-x

=0

so,

a^3+b^3+c^3=3abc

=>(x-2y)^3+(2y-3z)^3+(3z-x)^3=3.(x-2y)

(2y-3z)(3z-x)

Step-by-step explanation:

hope this help you......mark as brainliest dear ❤️

Thanks for asking☺️