Math, asked by Anonymous, 8 months ago

ques-- 1-tan square∅ divide by cot square∅ -1 = tan square ∅ please answer me i mark him as a branliest and give 5 star rating this is imp question for me

Answers

Answered by trashikagoyal
1

Step-by-step explanation:

 \frac{ 1 -  { \tan}^{2} a}{ { \cot }^{2}a - 1  } =  {tan}^{2} a

 \frac{1 -   \frac{ {sin}^{2}a }{ {cos}^{2}a }  }{ \frac{ {cos}^{2}a }{  {sin}^{2} a}  - 1}  =  \frac{ \frac{ {cos}^{2} a -  {sin}^{2} a}{ {cos}^{2}a } }{ \frac{ {cos}^{2} a -  {sin}^{2} a}{ {sin}^{2}a } }

 \frac{ {cos}^{2}a -  {sin}^{2} a }{ {cos}^{2}a }  \times  \frac{ {sin}^{2}a }{ {cos}^{2}a -  {sin}^{2} a }

 =   \frac{ {sin}^{2} a}{ {cos}^{2}a }  =  {tan}^{2}a  \:  \:  \:  \: hence \: proved

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