Question

Ques based on Motion
Class-9


A car having initial velocity 8 m/s moves with a constant acceleration of 8 m/s2 on a straight road. The ratio of distance travelled by car in first, third and fifth second of its motion is ____

a)1:3:5
b)1:5:9
c)3:7:11
d)3:7:13 ​

Answer 1

Answer:

b,1:5:9

I think it is helpful to you

Answer 2

Answer:

Given that,

The acceleration a=8m/s²

Initial velocity u=0m/s

We know that,

The displacement in the nth second

$=u+a(n−\frac{1}{2} )$

Now, the displacement in 5th second

$=0+8(5−\frac{1}{2})$

=36m

Hence, the distance covered by it in fifth second is 36 m.

_________________

I've just not given the ratio , you can find it from the above explaination given -,- !!