Question

Ques. Factorize : x^{2} + 10 x-21

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Answer 1

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Solution :

We have,

$= > {x}^{2} - 10 + 21 \\ = > factors \: of \: 21 \: are \: 3 \times 7 \\ = > - 10 = - 3 - 7 \: and - 3 \times - 7 = + 21 \\ = > {x}^{2} - 10x + 21 \\ = > {x}^{2} - 3x - 7x + 21 \\ = > x(x - 3) - 7(x - 3) \\ = > (x - 3)(x - 7) \\ \\ ans$

Or x = 3 and x= 7
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