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Question 1.6: Four point charges qA = 2 μC, qB = −5 μC, qC = 2 μC, and qD = −5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?

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Answers

Answered by abhi178
153
Four Charges are placed at corners of square of side length 10cm and a charge is placed at centre(O) of square as shown in figure.

forces of repulsion on 1μC charge at O due to 2μC charge at A and C are equal and opposite directions .
e.g., \bold{F_{CO}=F_{AO}=\frac{K(2\mu C)(1\mu C)}{(5\sqrt{2})^2}}
Therefore, these are cancelled.

Similarly, forces of attraction on 1μC charge at O , due to -5μC charges at B and at D are equal in magnitude and opposite in directions.
e.g., \bold{F_{OD}=F_{OB}=\frac{K(5\mu C)(1\mu C)}{(5\sqrt{2})^2}}
Therefore, these are also cancelled.
Hence, the net force on the charge of 1μC at O is zero.
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Answered by Anonymous
150
Hey mate!

Here's your answer!!

Four point charges qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5 µC are located at the corners of a square ABCD of side 10 cm.

Given that,

A square ABCD with each side = 10 cm = 0.1 m (divide by 100 to convert cm to m )
Charge qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5

And 1 µC placed at the centre of the square.
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