Question

Question 1:-


Find the Curved surface Area of a cylinder with Radius 14 , Height 20 . ( Take π = 22/7 )



Question 2:-

Find the Curved surface Area of a cylinder with Radius 21 , Height 10 . ( Take π = 22/7 )
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Answer 1

$\large\underline{ \underline{ \sf \maltese\red{ \: Question \: 1 :- }}}$

• Find the Curved surface Area of a cylinder with Radius 14cm , Height 20cm . ( Take π = 22/7 )

$\large\underline{ \underline{ \sf \maltese{ \: Diagram:- }}}$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{20\: cm}}\put(9,17.5){\sf{14\:cm}}\end{picture}$

$\large\underline{ \underline{ \sf \maltese{ \: Given :- }}}$

• Radius = ${ \boxed{14 \: cm}}$
• Height = ${ \boxed{20 \: cm}}$

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Curved \: Surface \: of \: Cyclinder \: = \:2\pi \: \times \: radius \: \times \: height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\bf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: \frac{22}{7} \times \: 14 \: \times \: 20 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: \frac{22}{\cancel\red{7}} \times \: \cancel\red{14} \: \times \: 20 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: 22 \times \: 2\: \times \: 20 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\bf{ Curved \: Surface \: of \: Cyclinder \: = \: 1760\:cm }}}$

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$\large\underline{ \underline{ \sf \maltese\red{ \: Question \: 2 :- }}}$

• Find the Curved surface Area of a cylinder with Radius 21 , Height 10 . ( Take π = 22/7 )

$\large\underline{ \underline{ \sf \maltese{ \: Diagram:- }}}$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{10\: cm}}\put(9,17.5){\sf{21\:cm}}\end{picture}$

.

$\large\underline{ \underline{ \sf \maltese{ \: Given :- }}}$

• Radius = ${ \boxed{21 \: cm}}$
• Height = ${ \boxed{10 \: cm}}$

.

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Curved \: Surface \: of \: Cyclinder \: = \:2\pi \: \times \: radius \: \times \: height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\bf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: \frac{22}{7} \times \: 21 \: \times \: 10 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: \frac{22}{\cancel\red{7}} \times \: \cancel\red{21} \: \times \: 10 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Curved \: Surface \: of \: Cyclinder \: = \:2 \:\times \: 22 \times \: 3\: \times \: 10 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\bf{ Curved \: Surface \: of \: Cyclinder \: = \: 1320\: cm }}}$

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More For Knowledge:-

$\boxed{\begin{minipage}{6.2 cm}\bigstar \:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{minipage}}$

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Answer 2

Answer:

CORRECT ANSWER⬆⬆⬆⬆

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