Question 1 Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 56. Find these numbers.
Answers
Answered by
0
Answer:
5,6,7
Step-by-step explanation:
Let's call the first integer:
n
Then the next two integers will be
(
n
+
1
)
and
(
n
+
2
)
If we then multiply them as described in the problem and sum these products to 56 we can write an equation as:
2
n
+
3
(
n
+
1
)
+
4
(
n
+
2
)
=
56
We can now solve this equation for
n
:
2
n
+
(
3
×
n
)
+
(
3
×
1
)
+
(
4
×
n
)
+
(
4
×
2
)
=
56
2
n
+
3
n
+
3
+
4
n
+
8
=
56
2
n
+
3
n
+
4
n
+
3
+
8
=
56
(
2
+
3
+
4
)
n
+
(
3
+
8
)
=
56
9
n
+
11
=
56
9
n
+
11
−
11
=
56
−
11
9
n
+
0
=
45
9
n
=
45
9
n
9
=
45
9
9
n
9
=
5
n
=
5
Therefore:
n
+
1
=
5
+
1
=
6
n
+
2
=
5
+
2
=
7
The three consecutive integers are: 5, 6, 7
Answered by
0
Answer:
7,8,9
Step-by-step explanation:
Similar questions
Math,
11 days ago
English,
11 days ago
Math,
11 days ago
Social Sciences,
21 days ago
Math,
21 days ago
Social Sciences,
9 months ago
Business Studies,
9 months ago