Question

Question 10 Solve the following system of inequalities graphically: 3x + 4y ≤ 60, x + 3y ≤ 30, x ≥ 0, y ≥ 0

Class X1 - Maths -Linear Inequalities Page 129

Answer 1

3x + 4y ≤60, x + 3y≤30, x≥0, y≥0

step1:- consider the inequations as strict equations.
3x + 4y = 60
x + 3y = 30,
x = 0,
y = 0

step2:- find the points on co-ordinate axes.
for, 3x + 4y =60
when, x =0,y = 15
when, y= 0,x = 20

for, x + 3y = 30,
when, x= 0, y = 10
when,y=0, x=30

x =0 will be y-axis.
y= 0, will be x-axis.

step3:- plot the graph of ,
3x + 4y = 60,
x + 3y = 30,
x = 0,
y = 0.

step4:- take a point (0,0) and put it in inequations.
3(0)+4(0) ≤60, which is true . Hence, the shaded region will be towards the origin.

(0)+3(0)≤ 30 , which is true. Hence, the shaded region will be towards the origin.

0≥0 which is true.hence, the shaded region will be towards the origin.

0≥0 which is true.hence, the shaded region will be towards the origin.

now, see attachment.
thus, common shaded region shows the solution of the inequalities.

Answer 2

Answer:

Step-by-step explanation:

Hello your ans is in given attachment below⬇⬇⬇⤵⤵⏬