Question

Question 9 Solve the following system of inequalities graphically: 5x + 4y ≤ 20, x ≥ 1, y ≥ 2

Class X1 - Maths -Linear Inequalities Page 129

Answer 1

5x + 4y ≤20, x≥1, y≥2

For solving this problem follow the below steps.

step1:- consider the inequations as strict equations.
5x + 4y = 20,
x = 1
y = 2

step2:- find the points on co-ordinate axes.
for, 5x + 4y = 20.
when, x = 0, y = 5
when, y = 0, x = 4

x = 1, is passing through point (1,0)and parallel to y-axis.

y=2, is passing through point(0,2) and parallel to x-axis.

step3:- plot the graph of,
5x + 4y = 20,
x = 1
y = 2

step4:- take a point (0,0) and put it in inequations.
5(0)+4(0) ≤20, which is true.hence the shaded region will be towards the origin.

(0)≥1 , which is true. Hence the shaded region will be towards the origin.

(0) ≥2 , which is true.hence the shaded region will be towards the origin.
now, see attachment.
thus, common shaded region shows the solution of the inequalities.