Question # 11 The factorization of 28a6-42 ab 5,3 is
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(a+b)^2 −11(a+b)−42
Let (a+b)=x, then we have
=x^2 −11x−42
=x^2 −14x+3x−42...[∵−42=−14×3and−11=−14+3]
=x(x−14)+3(x−14)
=(x−14)(x+3)
Substituting the value of x we get,
=(a+b−14)(a+b+3)
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