Question 12.34 0.3780 g of an organic chloro compound gave 0.5740 g of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.
Class XI Organic Chemistry : Some Basic Principles and Techniques Page 364
Answers
Answered by
15
Hi
Here is your answer,
The mass of the organic compound taken = 0.3780 g
Mass of AgCl formed = 0.5740 g
Percentage of chlorine = 35.5/143.5 × mass of AgCl formed/mass of substance taken × 100
= 35.5/143.5 × 0.5740/0.3780 ×100 = 37.566 %
Here is your answer,
The mass of the organic compound taken = 0.3780 g
Mass of AgCl formed = 0.5740 g
Percentage of chlorine = 35.5/143.5 × mass of AgCl formed/mass of substance taken × 100
= 35.5/143.5 × 0.5740/0.3780 ×100 = 37.566 %
Answered by
13
the mass of organic compound taken is 0.3780g
mass of AgCl formed = 0.5740g
we know,
atomic mass of Chlorine = 35.5 g/mol
molecular mass of AgCl = 108 + 35.5 = 143.5 g/mol
now,
Applying the relation,
The percentage of chlorine = (35.5/143.5) ×{mass of AgCl formed/mass of organic substance taken} ×100
= (35.5/143.5) ×{0.5740/0.3780} × 100
= (35.5 × 574 × 100}/{143.5 × 378}
= 37.566 %
hence, the percentage of Cl in the compound is 37.566% .
mass of AgCl formed = 0.5740g
we know,
atomic mass of Chlorine = 35.5 g/mol
molecular mass of AgCl = 108 + 35.5 = 143.5 g/mol
now,
Applying the relation,
The percentage of chlorine = (35.5/143.5) ×{mass of AgCl formed/mass of organic substance taken} ×100
= (35.5/143.5) ×{0.5740/0.3780} × 100
= (35.5 × 574 × 100}/{143.5 × 378}
= 37.566 %
hence, the percentage of Cl in the compound is 37.566% .
Similar questions