Question

Question 12
In the given below figure, AMIBC and AN is the bisector of ZBAC. If ZB = 70° and C = 35', then
ZMAN IS
70°
B
M
N
O 17.5"​

Answer 1

Answer:

Since, in ΔABC:

∠A+∠B+∠C=180°

⟹∠A=180°−55°−65°=60°.

Now, AN is angle bisector of ∠A then,

∠CAN=∠BAN=30°

Now, ∠ANM=∠NCA+∠CAN=55°+30°=85°........(Sum of two interior angles is equal to opposite exterior angle).

Now, in ΔANM:

∠AMN=90° and

∠MAN+∠ANM+∠AMN=180°

⟹∠MAN=180°−90°−85°=5°

Answer 2

Step-by-step explanation:

this is your answer. okk