Question 2.35 If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.
Class XI Structure of Atom Page 67
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diameter of C - atom = 0.15 nm = 1.5 × 10^-10 m
Length along which atoms are to be placed = 20cm = 2 × 10^-1 m
Then, number of C - atom can be placed in the given length = Length along which atoms are to be placed /diameter of C - atom
= 2 × 10^-1/1.5 × 10^-10
= 1.333 × 10^9 atoms
Length along which atoms are to be placed = 20cm = 2 × 10^-1 m
Then, number of C - atom can be placed in the given length = Length along which atoms are to be placed /diameter of C - atom
= 2 × 10^-1/1.5 × 10^-10
= 1.333 × 10^9 atoms
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