question 27 , 28 and 29
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ans.28 I think this will help you
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tanishkasri:
thanks a lot
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29. x+y = 4
Cubing both sides,
(x+y)³ = 4³
=> x³ + y³ + 3xy(x+y) = 64
=> x³ + y³ + 12xy = 64
x³ + y³ + 12xy - 64
= 64 - 64
= 0
If this helps u then only mark as brainliest.
Cubing both sides,
(x+y)³ = 4³
=> x³ + y³ + 3xy(x+y) = 64
=> x³ + y³ + 12xy = 64
x³ + y³ + 12xy - 64
= 64 - 64
= 0
If this helps u then only mark as brainliest.
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thank you so much
Don't forget to mark my answer as the brainliest
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