Question 4 plz solve this fast, tomorrow is my exam
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Hello Mate!
So, Question 4) 2x - 3y = 10 and xy = 8
2x - 3y = 10 __(i)
Squaring both sides of equation (i) we get,
( 2x - 3y )² = 10²
4x² + 9y² - 12xy = 100
4x² + 9y² - 12(8) = 100
4x² + 9y² - 96 = 100
4x² + 9y² = 100 + 96
4x² + 9y² = 196
Hence answer is 196.
Have great future ahead!
So, Question 4) 2x - 3y = 10 and xy = 8
2x - 3y = 10 __(i)
Squaring both sides of equation (i) we get,
( 2x - 3y )² = 10²
4x² + 9y² - 12xy = 100
4x² + 9y² - 12(8) = 100
4x² + 9y² - 96 = 100
4x² + 9y² = 100 + 96
4x² + 9y² = 196
Hence answer is 196.
Have great future ahead!
pbbharwdaj2:
bro, xy=10
No dear, xy = 8 please check the question once :)
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