question 5 and 6 tell me plssssssssssss
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^ answer 5
ABCD is trapezium
6:
as sum of angles of quadrilateral = 360°
therefore
4x + 48 + x + 4x + 3x = 360
12x + 48 = 360
12x = 312
i ) x = 26
therefore 4x = 104°
ii ) so angle ABC = 104°
as sum of angles in ∆ = 180°
therefore in ∆ACD
48 + 4x + <ACD = 180°
48 + 104° + <ACD = 180°
<ACD = 180 - 104 - 48
iii ) <ACD = 28°
ABCD is trapezium
6:
as sum of angles of quadrilateral = 360°
therefore
4x + 48 + x + 4x + 3x = 360
12x + 48 = 360
12x = 312
i ) x = 26
therefore 4x = 104°
ii ) so angle ABC = 104°
as sum of angles in ∆ = 180°
therefore in ∆ACD
48 + 4x + <ACD = 180°
48 + 104° + <ACD = 180°
<ACD = 180 - 104 - 48
iii ) <ACD = 28°
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