Question

Question 5
In the circuit shown in figure the rate of heat
produced in the 50



resistance is 20 Js -
mu
MW www
6Ω
4Ω
50
Only one option is correct
O
the current in the 60 resistor is
2A
8
O
the current in the 50 resistor is
IA
о
O
the rate of heat produced in the
40 resistor is 4 JS-
DO
the potential drop across
40 resistor is 8V​

Answer 1

Answer:

Question 5

In the circuit shown in figure the rate of heat

produced in the 50

resistance is 20 Js -

mu

MW www

6Ω

4Ω

50

Only one option is correct

O

the current in the 60 resistor is

2A

8

O

the current in the 50 resistor is

IA

о

O

the rate of heat produced in the

40 resistor is 4 JS-

DO

the potential drop across

40 resistor is 8V

Answer 2

Explanation:

H = I2 Rt (H/t) = I2R for 5Ω, (H/t) = 10 cal ∴ 10 = I12 × 5 I1 = √2A Now V = I1(5) = I2(4 + 6) ∴ 5I1 = 10I2 ∴ I2 = (I1/2) = (√2/2) = (1/√2)A Hence heat in 4Ω resistor per second = (H/t) = I22 R = (1/√2)2 × 4 = 2 calories