Question

Question 60:
The graph given alongside shows how the speed of a car changes with time:

(i) What is the initial speed of the car ?
(ii) What is the maximum speed attained by the car ?
(iii) Which part of the graph shows zero acceleration ?
(iv) Which part of the graph shows varying retardation ?
(v) Find the distance travelled in first 8 hours.

Lakhmir Singh Physics Class 9

Answer 1

Answer:

graph dal do tab n answer dunga

Answer 2

Hey Dear,

Corresponding diagram is missing from the question. I'll add that in image.

# Answers -

(i) Initial speed of the car i.e. speed at t = 0 h, v = 10 km/h.

(ii) Graph shows maximum peak at 35 km/h. Hence, maximum speed of the car is 35 km/h .

(iii) Acceleration will be zero when speed-time graph is parallel to time axis. Hence, acceleration will be zero between B and C.

(iv) Varying retardation means curve with decreasing slope. From the graph, C to D shows varying retardation.

(v) Distance traveled from A to B,

Distance = average velocity × time

s1 = (10+35)/2 × 3

s1 = 67.5 km

Distance traveled between B to C,

Distance = velocity × time

s2 = 35 × 5

s2 = 175 km

Total distance travelled in first 8 hours is,

s = s1 + s2

s = 67.5 + 175

s = 242.5 km

Thanks dear...