Question

Question 8.25 In Ostwald’s process for the manufacture of nitric acid, the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with 10.00 g. of ammonia and 20.00 g of oxygen?

Class XI Redox Reactions Page 274

Answer 1

                                        1100K
                  4NH₃ + 5O₂ --------------> 4NO + 6H₂O
                      |          |          Pt               |
              4 * 17g     5*32g                4*30g
              = 68g      = 160g               = 120g                       
  here you can see that,
      68g of NH₃ reacts with 160g of O₂
so, 10g of NH₃ reacts with 160/68 * 10 = 23.5 g of O₂
 
but here the available amount of O₂ is 20g, which is less than the required amount.hence, O₂ is limiting reagent.
  so, now,
   160g of O₂ produces 120g of  NO
so, 20g of O₂ produces 120/160 * 20 = 15g of NO
                       

Answer 2

Hi

Please see the attached file !

Hope it helps you!