Question 8 tan x= -4/3, x in quadrant II
Class X1 - Maths -Trigonometric Functions Page 82
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tanx = -4/3 where x is in 2nd quadrant.
but we know, in 2nd quadrant "sinx, cosecx" is positive and rest all terms are negative .
tanx = P/b = -4/3
h = √(4² +3²) = ±5
now, sinx = P/h = 4/5 [because x lies in 2nd quadrant ]
cosecx = 1/sinx = 5/4
cosx = b/h = - 3/5 [ because x lies in 2nd quadrant ]
secx = 1/cosx = -5/3
cotx = 1/tanx = 1/(-4/3) = -3/4
but we know, in 2nd quadrant "sinx, cosecx" is positive and rest all terms are negative .
tanx = P/b = -4/3
h = √(4² +3²) = ±5
now, sinx = P/h = 4/5 [because x lies in 2nd quadrant ]
cosecx = 1/sinx = 5/4
cosx = b/h = - 3/5 [ because x lies in 2nd quadrant ]
secx = 1/cosx = -5/3
cotx = 1/tanx = 1/(-4/3) = -3/4
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