Math, asked by Vamprixussa, 10 months ago

║⊕QUESTION⊕║
Everything around you is numbers.

CLASS 11
SEQUENCES AND SERIES

If \frac{5 + 9 + 13 + .............(n)terms}{7 + 9 + 1 1 + .... (n+1)terms} = \frac{17}{16}, find n

Answers

Answered by RvChaudharY50
2

Answer:

7

Step-by-step explanation:

(5+9+13+____________ n terms ) = n/2[2*5+(n-1)4]

= n/2[ 10+4n -4 ]

= n(2n + 3) ----------------------- ( equation 1 )

(7+9+11________ (n+1) terms ) = (n+1)/2[2*7 +(n+1-1)2]

= (n+1)/2 [ 14 + 2n]

= (n+1)(7 + n ) ---------------------- ( equation 2 )

Putting both equation equal to = 17/16 we get,

n(2n+3)/(n+1)(n+7) = 17/16

32n² + 48n = 17n² + 136n +119

15n² - 88n - 119 = 0

solving this

N = 7

Answered by channaisuperking04
0

Answer:

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