Question

question in pic please explain

Answer 1

$Given : 9 * (81)^x = \frac{1}{ 27^{x - 2} }$

$= \ \textgreater \ 9 * (81)^x = 27^{-x + 2}$

$= \ \textgreater \ 9 * (3^4)^x = (3^3)^{-x + 2}$

$= \ \textgreater \ 3^2 * 3^{4x} = 3^3^{(-x + 2)}$

= > 2 + 4x = 3(-x + 2)

= > 4x = -3x + 4

= > 7x = 4

= > x = 4/7.


Hope this helps!

Answer 2

see it is very easy
it's like 9 into 81 raise to x
and which is equal to 1 divided by 27 raise to x minus 2
now do you get me at the question that the basic idea of the question then you just start solving integers
fine darling??
now you can but solve it just be just wanted me to explain the question and u get it now I'll tried if u reply me to answer. will it ok if you don't get it then just reply?
Given:9∗(81)x=27x−21​ 

= 9 * (81)^x = 27^{-x + 2}= > 9∗(81)x=27−x+2 

= 9 * (3^4)^x = (3^3)^{-x + 2}
= > 9∗(34)x=(33)−x+2 

 

= > 2 + 4x = 3(-x + 2)

= > 4x = -3x + 4

= > 7x = 4

= > x = 4/7.

Bye dear darling sexy